Q2. Verify Lagrage’s theorem for f(x) = log x in (e^2 , e ^3).
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Answer:
Given f(x)−logx
f
′
(x)=
x
1
using Langrage's mean value theorm
f
′
(c)=
b−a
f(b)−f(a)
⇒
c
1
=
e−1
loge−log1
⇒
c
1
=
e−1
1
⇒c=e−1
Step-by-step explanation:
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