Question

Q2. What are the frequency and wavelength of a photon emitted during a transition from n=5 state to n=1 state.​

Answer 1

Answer:

7.01

Explanation:

Answer 2

Answer:

Given -

• $n_1=5$
• $n_2=1$

To Find -

• Wavelength ?
• Frequency ?

Solution -

From the formula to find the energy between the two orbits :

$\Delta E = 2.18\times10^{-18}\:J \bigg(\dfrac{1}{{n_1}^{2}}-\dfrac{1}{{n_2}^{2}}\bigg)$

Substituting and Calculating :

$\implies\Delta E = 2.18\times10^{-18}\:J \bigg(\dfrac{1}{{5}^{2}}-\dfrac{1}{{1}^{2}}\bigg)$

$\implies -2.09\times10^{-18} J$

Frequency :

$v = \dfrac{\Delta E}{h}$

$\implies v = \dfrac{-2.09\times10^{-18}}{6.626\times{10}^{-34}}$

$\implies v = 0.315\times {10}^{-18-(-34)}$

$\implies v = 0.315\times {10}^{16}$

$\implies v = 3.15\times {10}^{17}\:Hz$

Wavelength :

$\lambda=\dfrac{c}{v}$

$\implies \lambda = \dfrac{3.0\times{10}^{8}\:m{s}^{-1}}{3.15\times{10}^{17}\:Hz}$

$\implies\bf{952\:nm}$