Question

Q2.
Write the numbers given in the following place value table in decimal form.
Hundreds Tens Ones Tenths Hundredths Thousandths
(100) (10) (1)
1
1
10
100
1000
0
5
2
0
0
3
2
0
3
6
1
0
2.
5.
0
0
3
0.
2
(a)
(6)
(c)
(d)
(e)
9
0
1
1
2.
1
4
2
2
1
0​

Answer 1

Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.