Question

Q20 Find the least number which should be added to 18517 so that the sum is
exactly divisible by 125.​

Answer 1

${\huge{\rm{\red{\underline{\underline{Question:-}}}}}}$

• Find the least number which should be added to 18517 so that the sum isexactly divisible by 125.

${\huge{\rm{\blue{\underline{\underline{Answer:-}}}}}}$

• The no. is 108.

${\large{\rm{\huge{\underline{\underline{Explanation:-}}}}}}$

By using remainder theorem,

$: \implies\sf \: a = b\times q + r$

here, a = dividend, b = divisor, q = quotient, r = remainder

So,

$\large\sf \: 18517 = 125\times148 + 17 .........( 1 )$

But,

We need to add a number in order to make 18517 divisible by 125.

Hence, rewriting equation ( 1 ) We get,

$\large \sf \: 18517 = 125\times149 - 108$

If we add 108 to 18517 it is completely divisible by 125

${ \red {\sf {Remainder = -108}}}$

Therefore, least number which should be added to 18517 to make it divisible by 125 is 108.

Answer 2

Answer:-

• The number is 108

Explanation:-

》p = r × s + t

• Where p is dividend, r is divisor,

s is quotient and t is remainder.

So,

》18517 = 125 × 124 + 17......(1)

But, we have to find the no. which will be added to 18517. So, that it will be divisible by 125.

Now,

• If we will see the equation (1). So, we can see that (18517 + x) ÷ 125

》Therefore, 18517 = 125 × 149 + 108

Hence, the answer is 108.