Question

Q20) How much KClO3 should be heated to produce 2.24 L oxygen at STP?

Answer 1

HEYA.

2KClO3 -------------------> 2KCl + 3O2 

From the equation 3 moles(3x22.4lit) of O2 is liberated at STP from 2 moles(2x122.5=245g) of KClO3. 

2.24 liters of O2 at STP is released from ------------------------>? of KClO3 

2.24 x 245 / 3x22.4 = 8.16 lit 

STP and NTP conditions are same.


TYSM.#GOZMIT

Answer 2

Hey mate!

Here's your answer!!

The balanced chemical equation is

2KClO3 ➡ 2kCl + 3O2
2 moles 3 moles

2(39 + 35.5 + 48) 3 × 22.4L
= 245g at (NTP)

Stoichiometry indicates that

3 × 22.4L oxygen is produced from 245g KClO3

Therefore, 2.24 L oxygen is produced from

$\frac{245}{3 \times 22.4} = 8.17g$

Hope it helps you!!!
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