Q20. If Babita’s present age is X years. Then answer the following.
1. What will be her age after 3 years from now?
a) X – 3 b) X + 2 c) X = 3 d) X + 3
2. What will be her age 5 years back from now?
a) X + 5 b) X – 5 c) X – 4 d) X + 4
3. Babita’s elder sister is 7 years more than her age. What is her sister’s age?
a) X + 7 b) X – 7 c) X + 6 d) X – 6
4. Babita’s mother’s age two years more than 3 times Babita’s age. What is her mother’s age?
a) 3X + 3 b) 3X + 1 c) 3X + 2 d) 3X – 2
Answers
Answer:
1. (d) x+3
2.(b) x-5
3.(a) x+7
4. (c) 3x + 2d
Answer:-
1: d) x+3
2.b)x-5
3.a)x+7
4.c)3x+2
Explanation :-
Take your age as 20 years for understanding the question.
Que 1: Let if you are 20 year old so your age after 3 years will be 20 + 3 = 23 years so if your age is x so your age after 3 years from now will be x + 3.
Que 2: Your age is 20 years so what will be your age 5 years back so for that you will minus 5 from 20
that is 20-5 = 15 years so let you age be x so your age 5 years back from now will be x - 5 .
Que 3: Let you elder sister is 7 years more than your age and you age is 20 so your sister's age will be 20+7=27years .So if your age is x then your sister will be of x+7 years old.
Que 4: Your mother's age of 2 years more than three times if your age so your mother's age will be 3×20+2=62years old.Let your age be x so you mother will be of 3x+2 years.