Question

Q20. If Babita’s present age is X years. Then answer the following.

1. What will be her age after 3 years from now?

a) X – 3 b) X + 2 c) X = 3 d) X + 3

2. What will be her age 5 years back from now?

a) X + 5 b) X – 5 c) X – 4 d) X + 4

3. Babita’s elder sister is 7 years more than her age. What is her sister’s age?

a) X + 7 b) X – 7 c) X + 6 d) X – 6

4. Babita’s mother’s age two years more than 3 times Babita’s age. What is her mother’s age?

a) 3X + 3 b) 3X + 1 c) 3X + 2 d) 3X – 2​

Answer 1

Answer:

1. x+3

2. x-5

3. x+7

4. 3x+2

Answer 2

Answer:

1. d) , 2. b) , 3. a) , 4. c)

Step by-step explaination:

1. If her present age is x years, then after 3 years, it will be x +3 years .

Hence d)x+3 is correct

2. 5 years back means before 5 years that will be x - 5 years. hence, b)x-5 is correct .

3. 7 years more means we will add 7 to x or 7+x years. hence, a) x+7 is correct.

4. Three times babita's age means 3 × x years that is 3x and her mother is two years more than this result (3x) . Hence mother's age will be 3x+2 years. Hence , c)3x+2 is correct