Question

Q20.
If x is a positive integer such that the distance between points P(x,2) and Q (3,-6) is units, 10 then​

Answer 1

Answer:

Distance between two points

(x2−x1)

2

+(y2−y1)

2

(x−3)

2

+(2−(−6))

2

=10

(x−3)

2

+64

=10

Squaring both sides

(x−3)

2

+64=100

x

2

−6x−27=0

x

2

−9x+3x−27=0

x(x−9)+3(x−9)=0

x=−3,9

Taking positive value, x=9units

Answer 2

Answer:

Correct answer is x = 9

Explanation:

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