Question

Q20. In the given figure if AD
is the bisectos
of LA
show that
i AB>BD
ii) AC> CD
-​

Answer 1

Answer:

If AD is the bisector of ∠A of triangle ABC, show that AB>DB.  

Given AD is the bisector of ∠A of triangle ABC  

Hence ∠DAB=∠DAC  

∠BDA is the exterior angle of the ∆DAC  

Hence ∠BDA> ∠DAC  

or ∠BDA > ∠DAB Since ∠DAC=∠DAB  

→ AB > BD In a triangle sides opposite to greater angle is greater.

Step-by-step explanation:

PLS MARK ME BRAINLIST PLS PLS PLS !!!!!!!!!!!!!!

Answer 2

Answer:

good night everybody sweet dream...