Q21. Find the zeroes of the quadratic polynomials p(x) and verify the relationship between the zeros and the coefficients. p(x)= 3x² -x -4
Answers
Answer:
Given quadratic equation:
- 3x² - x - 4
Solving the quadratic equation by splitting the middle term we get,
→ 3x² + 3x - 4x - 4 = 0
→ 3x ( x + 1 ) - 4 ( x + 1 ) = 0
→ ( 3x - 4 ) ( x + 1 ) = 0
→ 3x - 4 = 0 ⇒ x = 4/3
→ x + 1 = 0 ⇒ x = -1
Relationship between zeros and coefficients:
- Sum of zeros = - ( coefficient of x ) / ( coefficient of x² )
- Product of zeros = ( constant term ) / ( coefficient of x² )
According to the given equation,
→ Sum of zeros = 4/3 - 1 = 1/3
→ Product of zeros = 4/3 × -1 = -4/3
Now comparing it with the relationship we get:
→ Sum of zeros = - ( - 1 ) / 3 = 1/3
→ Product of zeros = ( -4 ) / 3 = -4/3
Hence both of them tally each other.
LHS = RHS
Hence verified!!
Answer:
3x² - x - 4
Solving the quadratic equation by splitting the middle term we get,
3x² + 3x - 4x - 4 = 0
3x ( x + 1 ) - 4 ( x + 1 ) = 0
( 3x - 4 ) ( x + 1 ) = 0
3x - 4 = 0 ⇒ x = 4/3
x + 1 = 0 ⇒ x = -1
Relationship between zeros and coefficients:
Sum of zeros = - ( coefficient of x ) / ( coefficient of x² )
Product of zeros = ( constant term ) / ( coefficient of x² )
Sum of zeros = 4/3 - 1 = 1/3
Product of zeros = 4/3 × -1 = -4/3
Now comparing ,
Sum of zeros = - ( - 1 ) / 3 = 1/3
Product of zeros = ( -4 ) / 3
= -4/3
Hence both of them tally each other.
LHS = RHS
Step-by-step explanation:
i hope it helps uh.