Math, asked by gaytri9648, 5 months ago

Q21. Find the zeroes of the quadratic polynomials p(x) and verify the relationship between the zeros and the coefficients. p(x)= 3x² -x -4​

Answers

Answered by Steph0303
4

Answer:

Given quadratic equation:

  • 3x² - x - 4

Solving the quadratic equation by splitting the middle term we get,

→ 3x² + 3x - 4x - 4 = 0

→ 3x ( x + 1 ) - 4 ( x + 1 ) = 0

→ ( 3x - 4 ) ( x + 1 ) = 0

→ 3x - 4 = 0 ⇒ x = 4/3

→ x + 1 = 0 ⇒ x = -1

Relationship between zeros and coefficients:

  • Sum of zeros = - ( coefficient of x ) / ( coefficient of x² )
  • Product of zeros = ( constant term ) / ( coefficient of x² )

According to the given equation,

Sum of zeros = 4/3 - 1 = 1/3

→ Product of zeros = 4/3 × -1 = -4/3

Now comparing it with the relationship we get:

→ Sum of zeros = - ( - 1 ) / 3 = 1/3

→ Product of zeros = ( -4 ) / 3 = -4/3

Hence both of them tally each other.

LHS = RHS

Hence verified!!

Answered by itzyashica01
4

Answer:

\bf \huge \color{fuchsia} {Given:-}

3x² - x - 4

Solving the quadratic equation by splitting the middle term we get,

\color{purple} {\bf \huge \looparrowright} 3x² + 3x - 4x - 4 = 0

\color{purple} {\bf \huge \looparrowright} 3x ( x + 1 ) - 4 ( x + 1 ) = 0

\color{purple} {\bf \huge \looparrowright} ( 3x - 4 ) ( x + 1 ) = 0

\color{purple} {\bf \huge \looparrowright} 3x - 4 = 0 ⇒ x = 4/3

\color{purple} {\bf \huge \looparrowright} x + 1 = 0 ⇒ x = -1

\color{purple} {\bf \huge \looparrowright}Relationship between zeros and coefficients:

\color{purple} {\bf \huge \looparrowright} Sum of zeros = - ( coefficient of x ) / ( coefficient of x² )

\color{purple} {\bf \huge \looparrowright}Product of zeros = ( constant term ) / ( coefficient of x² )

\color{purple} {\bf \huge \looparrowright} Sum of zeros = 4/3 - 1 = 1/3

\color{purple} {\bf \huge \looparrowright}Product of zeros = 4/3 × -1 = -4/3

\color{purple} {\bf \huge \looparrowright}Now comparing ,

\color{purple} {\bf \huge \looparrowright} Sum of zeros = - ( - 1 ) / 3 = 1/3

\color{purple} {\bf \huge \looparrowright} Product of zeros = ( -4 ) / 3

= -4/3

\color{purple} {\bf \huge \looparrowright}Hence both of them tally each other.

\color{purple} {\bf \huge \looparrowright}LHS = RHS

\bf \huge \color{red} {Verified\checkmark}

Step-by-step explanation:

i hope it helps uh.

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