Question

Q21. If 42z6 is a multiple of 3, where z is a digit, what might be the values of z?

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Answer 1

Answer:

0,3,6,9are value's of z

explanation:-

Since 31z5 is a multiple of 3 ,the sum of its digits must be a multiple of 3 i.e. 3+1+z+5=9+z.

Hence 9+z is a multiple of 3

Since z is a single digit which can value from 0−9,

Possible values of z will be,

9+0=9

9+3=12

9+6=15

9+9=18

Thus, there can be four possible values i.e. 0,3,6 or 9

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Answer 2

Answer:

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