(Q21):
If a+3b=6 and ab=3, then the value of a² +9b² is:
a. 2
b: 12
c. 18
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ANSWER :-
(C) =18
Ab = 3
a = 3/b
a+3b = 6
3/b+3b = 6
3+3b² = 6b
3b²-6b+3 = 0
b²-2b+1 = 0
(b-1)² = 0
b-1 = 0
b = 1
a = 3/b
a = 3/1
a = 3
a²+9b²
= (3)²+9(1)²
= 9+9
= 18
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