Q21:- If AB = 12cm, BC = 16cm
and AB is perpendicular to BC,
then the radius of the circle
Passing through the points A, B,
C is : * option 1,2,3,4 please tell me
Answers
Answered by
0
Answer:
Given- A,B & C are points such that AB=12cm and BC=16cm and BC⊥AB.
To find out- the radius of the circle passing through A,B & C=?
Solution- BC⊥AB i.e ∠ABC=90
0
and ΔABC is a right one with AC as hypotenuse. ∴AC=
AB
2
+BC
2
=
12
2
+16
2
cm=20cm. So the circle passing through A,B & C will have its diameter as AC.
∴ Its radius=
2
1
×20cm=10cm.
Ans- Option C.
Attachments:
Answered by
0
ANSWER :
It is given that AB is perpendicular to BC, therefore, ∠ABC=90
∘
.
Every angle inscribed in a semicircle is a right angle.
Since the inscribed ∠ABC=90
∘
, the arc ABC is a semicircle.
Therefore, AC is the diameter of the circle passing through the centre.
Apply pythagorean theorem in triangle ABC, we have
AC
2
=AB
2
+BC
2
AC
2
=12
2
+16
2
AC
2
=144+256
AC
2
=400
AC=
400
AC=20cm
Diameter of circle is 20 cm and hence the radius is 10 cm as radius is half of diameter.
Similar questions