Math, asked by aditirichhariya, 7 months ago

Q21. In a ∆ PQR it is given that PQ = 6 cm, PR = 8 cm and PS is the bisector of ∠P. then QS : RS *


Answers

Answered by sanjaykaneriya23
0

Answer:

6/8

in ∆PQR

PQ/PR = QS/QR

6/8 = 6/8

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