Question

Q21. The value of sin8° x cox82°+ sin82° xcos8° is

 0

 1/2

 1

 None


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Answer 1

Answer:

1

Step-by-step explanation:

sinx = cos(90-x) and cosx=sin(90-x)

sin8 = cos(82)

cos(8) = sin(82)

Substitute in sin8° x cox82°+ sin82° xcos8° we get

=cox82° x cox82°+ sin82° sin82°

=(cox82°)^2 + (sin82°)^2

=1