Q21. The value of sin8° x cox82°+ sin82° xcos8° is
0
1/2
1
None
Answers
Answered by
0
Answer:
1
Step-by-step explanation:
sinx = cos(90-x) and cosx=sin(90-x)
sin8 = cos(82)
cos(8) = sin(82)
Substitute in sin8° x cox82°+ sin82° xcos8° we get
=cox82° x cox82°+ sin82° sin82°
=(cox82°)^2 + (sin82°)^2
=1
Similar questions