Question

Q22
A bag contains 8 red, 10 black and 15 green balls. Geet draws a ball out of the bag at random. What is the probability of NOT getting a green ball?​

Answer 1

Total balls = 8+10+15

                 = 33

No of balls which are not green = 8 + 10

                                                     = 18

P(Not getting a green ball) = No of balls which are not green/Total balls

                                             = 18/33

                                              = 6/11

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Answer 2

Answer:

Probability of not getting a green ball at random is $\frac{18}{33}$.

Step-by-step explanation:

Number of red balls = 8

Number of black balls = 10

Number of green balls = 15

Total number of balls = $8+10+15=3$

Probability of getting green ball = number of green balls / total number of balls

$P(G)=\frac{15}{33}$

Probability of NOT getting green ball = 1 - probability of getting green ball

$P'(G)=1-\frac{15}{33 } = \frac{33-15}{33} =\frac{18}{33}$