Question

Q22:- AD is a diameter of a
circle and AB is a chord. If AD
= 50 cm, AB = 48 cm, then the
distance of AB from the center
of the circle is : *
5 cm
6 cm
7 cm
8 cm​

Answer 1

OX is the perpendicular distance from centre O to the chord AB

∴AX=XB

Now,

AX+XB=AB

⇒2AX=AB

⇒2AX=30

⇒AX=  

2

30

​  

 

⇒AX=15

Again,

AO+OD=AD

⇒2AO=AD

⇒2AO=34

⇒AO=17

△AOX is a right angled triangle

∴AO  

2

=OX  

2

+AX  

2

 

⇒17  

2

=OX  

2

+15  

2

 

⇒OX  

2

=17  

2

−15  

2

 

⇒OX  

2

=  

64

​  

 

⇒OX=8cm