Question

Q22. Find the value of k for which the equation x2 + k(2x+k-1)+2 = 0 has real and equal
roots.​

Answer 1

Step-by-step explanation:

x2+k(2x+k-1)+2=0

x2+2xk+k2-k +2=0

x2+2kx +k2 -k+2=0