Question

Q22: Find the value of k, if t+4 is a factor of 2t4+kt-1.


Q23: Write any two solutions of the linear equation 3x+2y=9.​

Answer 1

Answer:

Q.22 : k = 127.75

Q.23 : (0, 9/2), (3, 0)

Step-by-step explanation:

Ques.22 :

f(x) = 2t⁴ + kt - 1

Given that (t + 4) is a factor of above polynomial.

t + 4 = 0

t = - 4

Now,

f(- 4) = 2(- 4)⁴ + k(- 4) - 1

0 = 2(256) - 4k - 1

0 = 512 - 4k - 1

0 = 511 - 4k

4k = 511

k = 511/4

k = 127.75

Ques.23 :

Given equation : 3x + 2y = 9

Putting, x = 0, we get

→ 3(0) + 2y = 9

→ 2y = 9

→ y = 9/2

Hence, one zero = (0, 9/2)

Putting y = 0, we get

→ 3x + 2(0) = 9

→3x = 9

→ x = 9/3

→ x = 3

Hence, another zero = (3, 0)

Answer 2

Answer:

this is the ans. hope it will helo you.