Question

Q22: If f(x)=x2-3x+1. find xeR such that f(2x) = f(x).​

Answer 1

Step-by-step explanation:

We have f(x) = x^2–3x+1

We need x such that f(2x)=f(x).

Now, as f(x) = x^2–3x+1

Then, f(2x) = (2x)^2–3(2x)+1 = 4x^2–6x+1

So, f(2x)=f(x)

=> 4x^2–6x+1 = x^2–3x+1

=> 4x^2–6x+1-x^2+3x-1=0

=> 3x^2–3x=0

=> 3x(x-1)=0

=> x=0 or (x-1)=0

=> x=0 or x=1

Thus, the values of x for which f(2x) = f(x) are 0 or 1.