Question

Q22 In given figure, find <BAC

(a) 30 degree
O b
(b) 50 degree
(C) 60 degree
(d) 90 degree​

Answer 1

Answer:

ANS IS 50°

Step-by-step explanation:

HERE ABCD IS A  CYCLIC QUADRILATERAL

SO ∠B+∠D=180

140+∠D=180

∠D=180-140

∠D=40

∠ACB=90  {∠OF SEMI CIRCLE IS 90°}

IN Δ ABC

∠BAC+∠ACB+∠CBA=180 {∠ SUM PROPERTY OF A TRIANGLE}

∠BAC+90+40=180

∠BAC+130=180

∠BAC=180-130

∠BAC=50°

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