Question

Q22 part 1 by multiplication method​

Answer 1

5x + 3y = 35

2x + 4y = 28

To solve this, it is best to eliminate the equation with the least coefficient of the unknown. Since the least coefficient is 2, we will eliminate x.

So, multiply equation1 by 2 and equation2 by 5. On doing this, we get

10x + 6y = 70 and

10x + 20y = 140

Subtracting the two equations, we get

14y = 70 or y = 70/14 = 5.

Substituting the value of 5 in equation2, we get

2x + 20 = 28 or

2x = 28 - 20 = 8.

Thus, x = 8/2 = 4.

Thus, x = 4 and y = 5.