Q22)Rachel, an engineering student, was
asked to make a model shaped like a cylinder
with two cones attached at its two ends by
using a thin aluminum sheet. The diameter of
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5cm and last your wish to get 10cm
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Volume of Air Contained in Model
= Volume of Model
= Volume of Cylinder + Volume of 1st cone + Volume of 2nd Cone
= πr²h + 1/3πr²h + 1/3πr²h
= (π × r² × h) + (1/3 × π × r² × h) + (1/3 × π × r² × h)
= (22/7 × (3/2)² × h) + (1/3 × 22/7 × (3/2)² × h) + (1/3 × 22/7 × (3/2)² × h)
= (22/7 × 9/4 × h) + (1/3 × 22/7 × 9/4 × 2) + (1/3 × 22/7 × 9/4 × h)
= (198/28 × h) + (22/217 × 9/4 × h) + (22/21 × 9/4 × h)
= (198/28 × (12 - 4)) + (22/21 × 9/4 × 2) + (22/21 × 9/4 × 2)
= (198/28 × 8) + (22/21 × 9/4 × 2) + (22/21 × 9/4 × 2)
= (198/28 × 8) + (22/21 × 9/2 × 1) + (22/21 × 9/2 × 1)
= (198/28 × 8) + (22/21 × 9/2) + (22/21 × 9/2)
= (1584/28) + (198/42) + (198/42)
= (56.57) + (4.71) + (4.71)
= 65.99 cm³
≈ 66 cm³
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