Question

Q23. A Bullet flying with a velocity of
50ms-1 hits 'a block of wood and
penetrates through a distance of 0.2
m before coming to rest. The Mass of
the bullet is 0.03kg. Calculate the
resistance offered by the block of
wood.​

Answer 1

Answer:

Initial velocity, u=50 ms

−1

Distance travelled, s = 0.2

Final velocity v = 0

Mass of the bullet, m = 0.03 kg

From the equation, v

2

=u

2

+2as

0=50

2

+2×a×0.2

a=−

0.4

2500

=−6250 ms

−2

∴ The resistance offered by the wood is

F=ma=0.03×6250=187.5N.

Explanation:

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