Question

Q23. Find the smallest 4 digit number such that when it is divided by 12, 18, 21 and
28, it leaves remainder 3 in each case.​

Answer 1

Answer:

the answer will be 1152

Step-by-step explanation:

here we have to find the smallest one so will do the lcm of all the given numbers.

their lcm will be 288.

now it is clear that 288 is the smallest digit than 999.

So making it 4 digit we need to multiply 288 by one of it's multiple but the no. will be greater when it is multiplied by 4.

then the answer will be 1152

Answer 2

Step-by-step explanation:

the smallest four digit no. is 1000

now find lcm of 12 18 21 and 28

12=2*2*3

18=2*3*3

21=3*7

28=2*2*7

lcm is 288

so multiply288 by 4

the result is 1152

it is indicated that there should be remainder 3

so your final answer is 1152+3

=1155

mark it dude✌✌✌✌☺☺☺☺