Question

Q23. In AABC, XY = 4 cm, YZ = 4.5 cm and XZ = 5 cm. X, Y and Z are mid-
points of AO, BO and CO respectively as shown in the figure. Find the perimeter
of triangle ABC.
​

Answer 1

Step-by-step explanation:

considering triangle AOB

given X,Y are the mid poinys of AO,BO

so XY//AB by mid point theorem

so

XY=AB/2

XY×2=AB

AB=8cm

similiarly in triangle AOC

X,Z are mid points of AO,OC

so

AC=2×XZ=10cm

Similarly in triangle

BOC

BC=2YZ=2×4.5=9cm

Perimeter =AB+BC+AC=10+9+8=27cm

Answer 2

Answer:

the perimeter is 26.

Step-by-step explanation:

ok, let's start that seeing that in the figure XY, YZ, and ZX are the lines the are joining the mid-point of AO, BO, and CO. means to put the midpoint theorem in it.

XY = 1/2 AB

YZ = 1/2 BC

ZX = 1/2 AC

Put the following things given in the question to these formulas.

XY = 1/2 18 = 9

YZ = 1/2 19 = 9.5

ZX = 1/2 16 = 8

9 + 9.5 + 8 = 26

and that's the answer. hope it helps

thank you:))