Q24. A gun fires bullets each of mass 1 g with velocity of 10 m/s by exerting a
constant force of 5 gwt. Then the number of bullets fired per second is
(i)
5
(ii) 50
(iv) 100
(iii) 10
Answers
Answered by
39
Correct Question :
A gun fires bullets each of mass 1 g with velocity of 10 m/s by exerting a constant force of 5g wt. Then the number of bullets fired per second is
i. 5
ii. 50
iii. 10
iv. 100
Solution :
Mass of the gun (m) = 1 g = 10⁻³ kg
Force (F) = 5g wt = 50 × 10⁻³ N
Velocity of the bullet (v) = 10 m/s
Time (t) = 1 s
➠ F = ΔP / Δt
➠ mg = nmv / t
➠ 50 × 10⁻³ = n ( 10⁻³ ) ( 10 ) / (1)
➠ 50 = 10n
➠ 10n = 50
➠ n = 5
Option i
Answered by
24
Given :
- A gun fires bullets each of mass 1 g with velocity of 10 m/s by exerting a constant force of 5g wt.
To find :
- What is the number of bullets fired per second.
According or the question :
- We need to take 1g into kg ans g wt into N units.
- Mass = 1 g → 10^-3 kg.
- Force = 5g wt → 50 × 10^-3 N.
Using formula
★ mg = nmv/t.
Calculations :
→ 50 × 10^-3 = n (10^-3) (10)/1
→ 50 = 10n
→ 10n = 50
→ n = 50/10
→ n = 5
Therefore, number of bullets is equal to 5.
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