Q24. Area of rectangular field A = 1 x b, where I = (2005)m and
b = (500+2)m. Find the percentage error in A.
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Answered by
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Answer:
6.5%
Explanation:
Relation between Area (A), Length (l) and breadth (b) is given by
A = l × b
differentiate both sides,
dA = b × dl + l × db
dividing by A both sides,
dA/A = b × dl/A + l × db/A
dA/A = b × dl/l × b + l × db/l × b
dA/A = dl/l + db/b
Hence , for finding error we have expression
\boxed{\boxed{\bold{\frac{\Delta{A}}{A}=\frac{\Delta{l}}{l}+\frac{\Delta{b}}{b}}}}
A
ΔA
=
l
Δl
+
b
Δb
Given, l = (200 ± 5) m and b = (50 ± 2)m
so, A = 200 × 5 = 1000
∆l = 5, ∆b = 2
We have to find % error ,
e.g., we have to find ∆A/A × 100 = ?
Now, ∆A/A = 5/200 + 2/50
Multiply 100 in both sides,
∆A/A × 100 = 5/200 × 100 + 2/50 × 100
% error = 5/2 + 4 = 2.5 + 4 = 6.5 %
Hence, percentage error in A = 6.5 %
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