Question

Q24:Find the values of x and y in the following parallelogram.
6y
120
(5x+10)
Ox=10° & y=20°
Oy=10° & x=20°
Ox=100° & y=20°
Ox=90° & y=200°​

Answer 1

Step-by-step explanation:

PQR+ext.∠Q=180

∘

[Linear pair]

∠PQR+80

∘

=180

∘

⇒∠PQR=100

∘

x+100

∘

=180

∘

[Supplementary angles of parallelogram]

x=80

∘

In △PSR,Z=∠SRP [Alternate angles]

∴80

∘

+60

∘

+Z=180

∘

⇒Z=180

∘

−140

∘

=40

∘

In △PQR,

40

∘

+y+100

∘

=80

∘

y=180

∘

−140

∘

=40

∘

Answer 2

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