Q24 In what ratio does the point (-4, 6) divide the line segment joining the points AC-6, 10)
and B 3.8)
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Step-by-step explanation:
Given In what ratio does the point (-4, 6) divide the line segment joining the points AC-6, 10) and B (3. 8)
- So we have x1 = - 6, y1 = 10
- x2 = 3, y2 = 8
- So the points x = - 4 and y = 6
- Using section formula we have
- x = m1x2 + m2x1 / m1 + m2
- So – 4 = m1 x 3 + 1 x – 6 / m1 + 1
- So – 4 = 3m1 – 6 / m1 + 1
- So – 4m1 – 4 = 3m1 – 6
- Or – 4m1 – 3m1 = - 6 + 4
- Or – 7m1 = - 2
- Or m1 = 2/7
- So the ratio will be 2:7
Reference link will be
https://brainly.in/question/4920413
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