Question

Q24 PQ is a tangent drawn at a point Pto a circle with centre O. OQ intersects the circle at R
such that OR = RQ .If PQ = 3V3 cm. find the radius of the circle.​

Answer 1

Answer:

PQ is a tangent drawn from a point P to a circle with centre O and QOR is a diameter of the circle such that ∠POR=120

o

, then ∠OPQ is

Step-by-step explanation:

30 degrees

Answer 2

Answer:

Please Mark me as Brainlisted ,Your answer

Step-by-step explanation:

Given- PQ is a tangent to a circle with centre O at Q. QOR is a diameter of the given circle so that ∠POR=120  

o

. To find out- ∠OPQ=?

Solution- QOR is a diameter.

∴OQ is a radius through the point of contact Q of the tangent PQ. ∴∠OQP=90  

o

 since the radius through the point  of contact of a tangent to a circle is perpendicular  to the tangent.∴∠OPQ+∠OQP=120  

o

 

(external angles of a triangle=sum of the internal opposite angles )

∴∠OPQ=120  

o

−90  

o

=30  

o

.

Answer -30Digree