Question

Q24.
Two particles are projected with same speed
but making different angles with horizontal
such that their ranges are equal. If the angle
of projection is a/3 and its maximum height
is y, then the maximum height of the other
is
(a) 3y
(c) y 12
(b) 2y
(d) y,/3

Answer 1

Explanation:

Ranges are equal for complimentary angle

So angle of projection would be

3

π

&(

2

π

−

3

π

)i.e.

3

π

&

6

π

For first stone y

1

=

2g

u

2

sin

2

3

π

=

2g

u

2

(

4

3

)or

2g

u

2

=

3

4y

1

For second stone, maximum height =

2g

u

2

sin

2

π/6

=

2g

u

2

(

4

1

)=(

3

4y

1

)(

4

1

)=

3

y

1

Answer 2

Explanation:

y/3 is the answer of the question