Math, asked by TANVI3007, 9 months ago

Q25 Find the smallest square no. (perfect sq.) which is divisible by each of 6, 9 and 15.

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Answers

Answered by Anonymous

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Find the LCM of 6, 9 and 15

6 = 3 × 2

9 = 3 × 3

15 = 5 × 3

Here, only 5 and 2 are not in pairs.

LCM = 90

<u>Step 2</u> :- Multiply the numbers which are not in pair to the LCM

=> 90 × 2 × 5 = 900

\therefore{} The square number is 900

• 900 is the square of 30

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Answered by avitaylor101

Step-by-step explanation:

Here,

Square of 90 is divisible by 6 , 9 , 15

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