Q25 Find the smallest square no. (perfect sq.) which is divisible by each of 6, 9 and 15.
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Find the LCM of 6, 9 and 15
6 = 3 × 2
9 = 3 × 3
15 = 5 × 3
Here, only 5 and 2 are not in pairs.
LCM = 90
<u>Step 2</u> :- Multiply the numbers which are not in pair to the LCM
=> 90 × 2 × 5 = 900
\therefore{} The square number is 900
• 900 is the square of 30
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Step-by-step explanation:
Here,
Square of 90 is divisible by 6 , 9 , 15
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