Question

Q25. Mass M1 = 1 kg is suspended from a light string to form a
simple pendulum. Length of the string is L = 2 m. It is taken aside
through 600
is released. At the lowest point, M1 collides with a sta-
tionary mass M2 = 200 g. After collision M1 stops and M2 begins
to move with some speed on a smooth surface. The surface gradu-
ally curves upwards and becomes vertical. Calculate the height to
which M2 will ultimately rise above the ground level. Express your
answer in meter. Neglect air resistance.

Answer 1

Answer:

Explanation:

The mass =m

Length=l

The acceleration of the string is  

r

v  

2

 

​  

 and the force due to tension T is T  

r

dl

​  

 where dl is the length of an element of string. Both directed towards the centre of curvature

If T  

r

dl

​  

=m  

r

dl×v  

2

 

​  

 

(m being mass/unit length)

then there is no need for the tube.

v  

2

=  

m

T

​