Question

Q25. There is a circuit with six resistors in series,
R1= 2 ohm, R2= 6 ohm, R3= 5 ohm, R4= 10 ohm, R5= 10 ohm,R6= 12 ohm
and a voltage of 13.8 v. Find the potential difference across R2.
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Answer 1

Question ⁉️

There is a circuit with six resistors in. series, R1 = 2 ohm , R2 = 6 ohm , R3 = 5 ohm , R4 = 10 ohm , R5 = 10 ohm , R6 = 12 ohm

and a voltage of 13.8 V . Find potential difference across R2 ?

Solution

Given -

R1 = 2 ohm

R2 = 6 ohm

R3 = 5 ohm

R4 = 10 ohm

R5 = 10 ohm

R6 = 12 ohm

voltage = 13.8 volt

for series combination ,

equivalent resistance = R1 + R2 + R3 + R4 + .....

R eq = R1 + R2 + R3 + R4 + R5 + R6

R eq = ( 2 + 6 + 5 + 10 + 10 + 12 ) ohm

R eq = 45 ohm

current through the wire is same across all the resistors as they are connected in series....

therefore , current through the wire is

current ( I ) = v / R eq

current = 13.8 volt / 45 ohm

current = 0.30 ampere

potential accross R2 = Current × R2

= 0.30 ampere × 6 ohm

= 1.8 volt