Question

Q26. From the sum of 2y+3y2 ,y?+yz+z?
Subtract the sum of 3y?+z²,-y?+yz pls don't spam

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Answer 1

Answer:

Ur answer is 2y + 3y^2 + 2yz + z + z^2

Step-by-step explanation:

(2y+3y2 +y+yz+z) - (3y+z²+-y+yz)

First Combine the like terms

y(2+1-1) + y^2(3) + yz(1+1) + z(1) + z^2(1)

= 2y + 3y^2 + 2yz + z + z^2

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Answer 2

Step-by-step explanation:

Sum:

2y + 3y + y + yz + z

= 6y + yz + z

Sum:

3y + z² + (-y) + yz

= 3y + z² - y + yz

= 3y - y + z² + yz

= 2y + z² + yz

Subtraction:

6y + yz + z - 2y + z² + yz

= 6y - 2y + yz + yz + z + z²

= 4y + 2yz + z + z²

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