Question

Q26. Iftan A-tan B = x and cot B - cot A = y, then the value of cot (A - B) is
(A) X + y
(B) 1/x + y
0 (C) x + 1
O (D) 1/x + 1/7
ans
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Answer 1

Step-by-step explanation:

tanA−tanB=x, & cotB−cotA=y ⇒

tanAtanB

tanA−tanB

=y

tanAtanB=

y

x

Now cot(A−B)=

tanA−tanB

1+tanAtanB

=

x

1+

y

x

=

x

1

+

y

1