Math, asked by vansh00117778, 8 months ago

Q26. Seema is twice as old as Sweta. Five year ago, Seema was 4 times older than Sweta. Find their present age.

Answers

Answered by saniamittal

3

Step-by-step explanation:

Let Sunita's present age = x years

Then Reena present age = 2x years

Three years ago

(2x-5) = 4(x-5)

2x - 3 = 4x - 20

or x = 9

Reena age = 2x = 2*9= 18 year.

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