Question

Q26. The diameter of a roller, 120cm long is 84cm. It takes 500 complete revolutions to level a playground. Find the cost of levelling it at the rate of ₹25 per sq. metre.​

Answer 1

Answer:

Rs. 39,600/-.

Step-by-step explanation:

Given;

diameter= 84cm

.°. radius= 42cm

Height= 120cm

Therefore; CSA of a Cylinder= 2pi r h

=2 × 22/7 × 42 × 120

=44× 6 × 120

=31680 cm^2

Total area of the play ground = 31680 × 500

=15840000 cm^2

= 1584 m^2

Cost-

Rs. 25 for 1 m^2

For 1584 m^2 = 1584 × 25

= Rs. 39600

.°. the cost will be Rs. 39,600/-.