Q26. The diameter of a roller, 120cm long is 84cm. It takes 500 complete revolutions to level a playground. Find the cost of levelling it at the rate of ₹25 per sq. metre.
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Answer:
Rs. 39,600/-.
Step-by-step explanation:
Given;
diameter= 84cm
.°. radius= 42cm
Height= 120cm
Therefore; CSA of a Cylinder= 2pi r h
=2 × 22/7 × 42 × 120
=44× 6 × 120
=31680 cm^2
Total area of the play ground = 31680 × 500
=15840000 cm^2
= 1584 m^2
Cost-
Rs. 25 for 1 m^2
For 1584 m^2 = 1584 × 25
= Rs. 39600
.°. the cost will be Rs. 39,600/-.
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