Question

Q27. In how many ways can be
letters of the word PERMUTATIONS
be arranged if the
» (i) words start with P and ends with
S?
(ii) vowels are all together?​

Answer 1

Answer:

no of ways the words start with P and ends with S =

P(10, 10)/P(2,2) = 10! / 2! = 1814400

no of ways vowels all are together = P(8,8) × P(5,5) / P(2,2)

= 40320 × 120 / 2 = 2419200