Q28: The angle of elevation to the top of a tower observed by a person is 45°. If he walls 50
meters towards the tower he finds the angle of elevation increase to 60°. How far the person is away
from the tower at this position and what is the height of the tower. Round off the answers to the
nearest meter.
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Let the height of tower be (x+50) . The angle of elevation as seen by observer is 45°. So the triangle formed is 45°-45°-90° triangle and hence the observer is also at (x+50) m from the tower.
When he moves 50m closer to the tower, he is at distance x from the tower and elevation angle increased to 45°+15°=60°. The new triangle formed is 30°-60°-90° triangle with two side as (x+50) and x , i.e. the hieght of tower and new distance of observer from the tower, resptectively. Therefore -
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