Math, asked by vvshiporkarvs, 3 months ago


Q28. The external dimensions of a open wooden box are 98cm by 84cm by 77cm. If the wood is 2 cm thick all
around, find the volume of the wood used to make the box. Also find the weight of the box in Kgs if 1cm of
wood weighs 0.8 gm
एक खुले लकड़ी के बक्से की बाहरी भुजाए क्रमशः 98 सेमी. x 84 सेमी. x 77 सेमी. है। यदि लकड़ी चारों ओर से 2 सेमी, मोटी हो तो इस बक्से
को बनाने में लगी लकड़ी का आयतन ज्ञात कीजिए। यदि 1 सेमी3 लकड़ी का वजन 0.8 ग्राम हो तो बक्से का भार ज्ञात कीजिए।
11
I/0/​

Answers

Answered by onlytanutanutanu001
4

Answer:

HOPE THE BELOW HELPS YOU

Step-by-step explanation:

Given external dimensions i.e. length, breadth, height of the box are 98 cm, 84 cm, 77 cm respectively.

Internal dimensions would be

length  = 98-2-2 = 94 cm

breadth = 84-2-2 = 80 cm

height = 77-2-2 = 73 cm

The Capacity of the box would be internal volume of box i.e.

V = 94*80*73 =548960 cm³

The volume of wood would be equal to external volume - internal volume i.e.

98*84*77 - 94*80*73 =  84904 cm³

weight of the box would be equal to volume * density = 84904* 0.8 gm = 67923.2 gm = 67 kg

Similar questions