q289
pls solve this q289 as fast as u can
thanks
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Answered by
1
pq + qr = 7
pq * qr = 12
therefore pq = 4
by pythogorean theorem
pr = 5
pq * qr = 12
therefore pq = 4
by pythogorean theorem
pr = 5
Answered by
1
PQ+QR=7
PQ=7-QR
Area of rectangle=length×breadth
=PQ×QR
=(7-QR)×QR
=7QR-QR²
According to the question,
7QR-QR²=12
QR²-7QR+12=0
QR²-3QR-4QR+12=0
QR(QR-3)-4(QR-3)=0
(QR-4)(QR-3)=0
QR-4=0 QR-3=0
QR=4 QR=3
The value of PQ=3,If QR=4
PQ=4 ,If QR=3
case -1:
PQ=3,QR=4
by pythagoras theorem,
PR=√(3²+4²)
=√25
=5
case-2:
if PQ=4,QR=3
by pythagoras theorem,
PR=5
PQ=7-QR
Area of rectangle=length×breadth
=PQ×QR
=(7-QR)×QR
=7QR-QR²
According to the question,
7QR-QR²=12
QR²-7QR+12=0
QR²-3QR-4QR+12=0
QR(QR-3)-4(QR-3)=0
(QR-4)(QR-3)=0
QR-4=0 QR-3=0
QR=4 QR=3
The value of PQ=3,If QR=4
PQ=4 ,If QR=3
case -1:
PQ=3,QR=4
by pythagoras theorem,
PR=√(3²+4²)
=√25
=5
case-2:
if PQ=4,QR=3
by pythagoras theorem,
PR=5
mahek7:
thankyou so much for spending ur precious time for this sol so grateful
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