Math, asked by mahek7, 1 year ago

q289
pls solve this q289 as fast as u can
thanks

Attachments:

Answers

Answered by mukunth1
1
pq + qr = 7
pq * qr = 12
therefore pq = 4
by pythogorean theorem
pr = 5
Answered by lekhahasa
1
PQ+QR=7
PQ=7-QR

Area of rectangle=length×breadth
                           =PQ×QR
                           =(7-QR)×QR
                           =7QR-QR²
According to the question,
7QR-QR²=12
QR²-7QR+12=0
QR²-3QR-4QR+12=0
QR(QR-3)-4(QR-3)=0
(QR-4)(QR-3)=0

QR-4=0       QR-3=0
QR=4           QR=3

The value of PQ=3,If QR=4
PQ=4 ,If QR=3

case -1:
PQ=3,QR=4
by pythagoras theorem,
PR=√(3²+4²)
     =√25
     =5

case-2:
if PQ=4,QR=3

by pythagoras theorem,
PR=5 



mahek7: thankyou so much for spending ur precious time for this sol so grateful
Similar questions