Q28in the attached file
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value of x for this question is -2
((2x+1)^2+(x-1)^2)/((x-1)(2x+1))=2
(4x^2+1+4x+x^2+1-2x)=2(x-1)(2x+1)
5x^2+2x+2=(2x-2)(2x+1)
5x^2+2x+2=4x^2+2x-4x-2
x^2+4x+4=0
x^2+2x+2x+4=0
x(x+2)+2(x+2)=0
(x+2)(x+2)=0
x=-2
((2x+1)^2+(x-1)^2)/((x-1)(2x+1))=2
(4x^2+1+4x+x^2+1-2x)=2(x-1)(2x+1)
5x^2+2x+2=(2x-2)(2x+1)
5x^2+2x+2=4x^2+2x-4x-2
x^2+4x+4=0
x^2+2x+2x+4=0
x(x+2)+2(x+2)=0
(x+2)(x+2)=0
x=-2
twinkle1125:
which answer,???
Answered by
2
Heya!!
( x - 1 )² + ( 2x +1 )² = 2 ( x -1 ) ( 2x + 1 )
x² + 1 -2x + 4x² +1 + 4x = 4x² +2x -4x -2
x² + 4x + 4 = 0
x² + 2x + 2x +4 = 0
x ( x +2 ) + 2 ( x + 2 ) = 0
x = -2
Have a nice day ahead.
( x - 1 )² + ( 2x +1 )² = 2 ( x -1 ) ( 2x + 1 )
x² + 1 -2x + 4x² +1 + 4x = 4x² +2x -4x -2
x² + 4x + 4 = 0
x² + 2x + 2x +4 = 0
x ( x +2 ) + 2 ( x + 2 ) = 0
x = -2
Have a nice day ahead.
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