Question

Q29.
(a) Reduce X’Y’Z’ + X’Y Z’ + XY’Z’ + XYZ’

(b) Simplify AB’CD’ + AB’CD + ABCD’ + ABCD

Anyone Know?????????

Answer 1

Answer:

(a) x'y+x'y is XOR. So you can simplify to find z(x+y) +xy because z(x'y +xy') is z when x ! = y and xy when x==y

the (x+y) after z is necessary to disallow influence of z when x==y==0.....

(b) A'(B'CD +B'CD+BC'D)

+ A (B'CD +BCD)

= A'(C'D (B'+B ) +B'CD)+ A(CD (B' +B))

= A'(C'D (1) +B'CD)+ A (CD (1) )

= A'C'D + A'B'CD +ACD

= D(A'C' + AC ) +A'B'CD

= D ( A xnor C ) + A'B'CD

= D ( ( A xnor C )+ A'B'C ).......

Explanation:

Hope it helps you!