Math, asked by chaudhryrakshit, 5 hours ago

Q29 ) Sita's mother's present age is 20 years more than 2 times her age. . Sita's age , 5years from now will be 1/3 her mother's present age. Find their present ages.​

Answers

Answered by tennetiraj86
12

Step-by-step explanation:

Given :-

Sita's mother's present age is 20 years more than 2 times her age.

Sita's age,5years from now will be 1/3 her mother's present age.

To find :-

Their present ages.

Solution :-

Let the present age of Sita be X years

The present age of Sita's mother

= 20 years more than 2 times Sita's age

= (2X+20) years

Therefore, The present age of Sita's mother

= (2X+20) years

Sita's age after 5 years = (X+5) years

Sita's mother's age after 5 years

= (2X+20)+5

= (2X+25) years

According to the given problem

Sita's age after 5 years = 1/3 of her mother's age

=> X+5 = 1/3 of (2X+25)

=> X+5 = (1/3) × (2X+25)

=> X+5 = (2X+25)/3

On applying cross multiplication then

=> 3(X+5) = 2X+25

=> 3X+15 = 2X+25

=> 3X-2X = 25-15

=> X = 10 years

Therefore, The value of X = 10 years

The present age of Sita = 10 years

The present age of Sita's mother

= (2×10+20) years

= 20+20

= 40 years

Answer:-

The present age of Sita = 10 years

The present age of Sita's mother

= 40 years

Check :-

The present age of Sita = 10 years

The present age of Sita's mother

= 40 years

= (2×10)+20

= 20 more than twice the present age of Sita

After 5 years Sita 's and Sita's mother's ages will be 10+5 = 15 years and

40+5 = 45 years

We have,

15 = 45/3

Sita's age , 5years from now will be 1/3 her mother's present age.

Verified the given relations in the given problem.

Answered by Anonymous
19

Given Information :-

  • Sita's mother's present age is 20 years more than 2 times her age.
  • After 5 years, Sita's age will be 1/3 of her mother's age

To Find :-

  • Their present ages

Solution :-

Let the age of Sita be x. Therfore, according to the give information :-

  • Sita's mother's age = 20 + 2x
  • Sita's age after 5 years = 1/3 ( 25 + 2x )
  • Sita's age after 5 years = x + 5

Now we will compare these Informations.

 \sf  : \longrightarrow x + 5 =  \dfrac{1}{3}  \{25 + 2x \} \\  \\  \sf  : \longrightarrow 3 \{x + 5 \} = 25 + 2x \:  \\  \\  \sf  : \longrightarrow 3x + 15 = 25 + 2x \:  \:  \:  \:  \\  \\  \sf  : \longrightarrow  3x - 2x = 25 - 15 \:  \:  \:  \:    \\  \\  \sf  : \longrightarrow x = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:

Therefore, present age of :-

  • Sita = x = 10
  • Sita's mother = 2x + 20 = 20 + 20 = 40

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