Q2If a double ordinate of the parabola y= 2ax is of length 4a, then the lines from the vertex to its two ends are at an angle ofOps: A. OoºB. O 90°c. o 60°D. 45°
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If x=2at2,y2=(2at)2⟹y=±2at
WLOG the two ends be P(2ap2,2ap) and Q(2aq2,2aq)
So, the gradient of PQ will be
2a(q−p)2a(q2−p2)=1q+p
But it's perpendicular to the axis y=0 of the parabola
⟹q+p=0⟺q=−p
Now the length of PQ will be
(2ap2−2aq2)2+(2ap−2aq)2−−−−−−−−−−−−−−−−−−−−−−−−√=4a|q|
Finally, if O(0,0) is vertex, what will be product of gradients of OP,OQ?
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