Question

Q3-4) The First term of an A.P,
is 6 and the common
difference is 3. *
Find S10​

Answer 1

Answer:

Step-by-step explanation:

$a = 6$

$d = 3$

$a_{10} = a+9d$

$a_{10} = 3 +9*3$

$a_{10} = 30$

$s_{10} = \frac{10}{2} (6 +(9*3))$

$s_{10} = 5 (6 + 27)$

$s_{10} =5*33$

$s_{10} = 165$

Hence proved

Answer 2

Answer:

s10=195

Step-by-step explanation:

a=6 ,d=3 ,n=10

$sn = \frac{n}{2}2a + (n - 1)d$