Q3. A bag contains 5 blue and 4 black balls. Three balls are drawn at random. What is the probability that 2 are blue and 1 is black
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We have total (5+4) =9 ball.
Hence, ways of selecting 3 balls out of 9 balls is 9c3 i.e 84 .
Now,ways of getting 2 blue balls out of 5 is 5c2 i.e 10 and way of getting 1 black ball out of 4 is 4c1 i.e 4.
So,the Probablity of getting 2 blue balls and 1 black ball out of 3 chosen balls is (10×4)/84 = 10/21.
HOPE , IT HELPS ....
We have total (5+4) =9 ball.
Hence, ways of selecting 3 balls out of 9 balls is 9c3 i.e 84 .
Now,ways of getting 2 blue balls out of 5 is 5c2 i.e 10 and way of getting 1 black ball out of 4 is 4c1 i.e 4.
So,the Probablity of getting 2 blue balls and 1 black ball out of 3 chosen balls is (10×4)/84 = 10/21.
HOPE , IT HELPS ....
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