Question

Q3. A body A of mass 3.0kg and a body B of mass 10 kg are dropped
simultaneously from a height of 9m. Calculate their Momenta, their potencial
energies and kinetic energies when they are 10m above the ground​

Answer 1

Explanation:

300 potential energy of A

1000 potential enetgy of B

Answer 2

Answer:

DISTANCE TRAVELLED s = 14.9 - 10 = 4.9

u = 0

a = g = 9 . 8

v ^ 2 = u ^ 2 + ( 2as ) = 2 * 9 . 8 * 4.9 = 96 . 04

v = 9 . 8

p ( momentum ) = mv = 3 * 9 . 8 = 29 . 4

K . E . = m (v ^ 2 ) / 2 = 3 * 96 . 04 / 2 = 144 . 06

P . E . = mgh = 3 * 9 . 8 * 10 = 294

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